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Straight Running Torpedo Attacks
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Optimum Firing Position Within the TDZ
Barring flukes in the exploder mechanism,
one ideally wants the torpedo's path to cross the target's
path at a 90° angle. This
means TA + AOB = 90° for an
ideal shot. Such an interception ensures the maximum length
of the target is exposed to the attack. Under actual conditions
you will be doing well to get a shot having TA + AOB within
± 30°
of the target's beam.
If the target is stationary, we want
to shoot from its beam (AOB = 90°
, Port or Starboard) and SA = 0°.
You will rarely get this opportunity. Most of the time you
will need to fire from forward of the target's beam in order
to get a TA + AOB = 90° .
Numerically TA = SA, so we can say SA + AOB = 90°.
In the special case of SA + AOB = 90°
, SA will equal the angle forward of target's beam we need
to be in order to get a crossing angle of 90°
. See Figure 3.
Figure 3 - Special Case
of 90° Crossing Angle
Just how much does SA need to be?
That depends on the ratio of (Target Speed)/(Torpedo Speed),
which I call K. The following table shows what SA must be
to yield a 90° crossing shot
for various values of K. You can see that a high torpedo speed
brings many advantages - the higher the torpedo speed, the
lesser the value of K, thus the lesser value of SA we need
to get a more optimum shot. A higher torpedo speed also reduces
time to target, which reduces the target's ability to evade.
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